Rev. July 31, 2016

The time integral of baryon space divided by the integral of baryon time equals the derivative of baryon space divided by the derivative of baryon time.

integral(NV)dt / integral(t)dTau = dzA/dt / dt/dTau

integral(NV)dt / ((1/2) t^2) = dzA/dt / 1

Convert back to seconds:

integral(NV)dt = d/dt (zA) * C/2

NVt = d((1/2) a t^2)/dt * CA/2

NVt = a t * CA/2

NVt = a t * C(4 pi RR)/2

a = NV / C(4 pi RR)/2

a = NV / (C 2 pi RR)

a = MV / (2 pi C RR (mp))

Where N is number of baryons in a star, V is baryon volume 3.6*10^-45 meter^3, z is height fallen in an experiment, A is area of star at distance R from the center of the star, C is 5.131534*10^-9 second^2, m is a test mass, M is a star mass, (mp) is proton mass:

N = M/(mp)

Newton's force formula uses mass but the new formula does not, it uses Volumes. The mass of matter is proportional to the Volume of matter, so some people mistake mass for a source of gravity.

Rev. 2016.1.8

####

End of Law, Revised January 8, 2016, Alan Folmsbee, Wailuku

Matter causes gravity. Protons and neutrons are matter with volume. Mass does not cause gravity; it is an area. The Law of Gravity is defined without mass. The acceleration of gravity (a) near a planet, depends on volumes of free space draining into baryons and time growing out of baryons.

The momentum conservation revealed on the page for "Newton's G Derived" is used to write the law of gravity.

V

p

V

V

V

z = height fallen in 1 second = (1/2 a t

z/(1 second) = average velocity in the experiment dropping an apple for 1 second

The derivative of z/(1 sec) is acceleration a

A is area of a sphere centered on the planet's center, with a radius R from the center of the planet (4 pi R

tau = 5.131534 nanoseconds = τ

~~
dp~~

~~dp~~

~~dp~~

C

C

2a π R

Solve for a = g = gravitational acceleration

g = MV / (2mC

#
g = MV / (2 π m C

For example, on Mars:

M = 0.641740*10

V = 3.591364*10

m = 1.673800*10

C

C

R = 3.396200*10

R = length from the planet center to the apple drop point

Use the Law of Gravity to calculate g and compare it with NASA's g.

Multiply mantissa'a alone, then add exponents

g = 0.64174*3.591364/(2*3.141592654*1.673800*5.131534*1.153417)

g = 0.03702555 mantissa

add exponents

x = 24-45+27+9-13 = 2

so

That confirms The Law of Gravity.

g = (M/R

The momentum in baryons equals the momentum of any shell around a planet, where a shell is a height fallen times the area of a spheroid centered on the planet's center.

The linear momentum in a proton equals the momentum of a shell that surrounds the proton. That is the law of gravity.

December 23, 2015, Alan Folmsbee, Wailuku

The time integral of baryon space divided by the integral of baryon time equals the derivative of baryon space divided by the derivative of baryon time.

integral(NV)dt / integral(t)dTau = dzA/dt / dt/dTau

integral(NV)dt / ((1/2) t^2) = dzA/dt / 1

Convert back to seconds:

integral(NV)dt = d/dt (zA) * C/2

NVt = d((1/2) a t^2)/dt * CA/2

NVt = a t * CA/2

NVt = a t * C(4 pi RR)/2

a = NV / C(4 pi RR)/2

a = NV / (C 2 pi RR)

a = MV / (2 pi C RR (mp))

N = M/(mp)

Newton's force formula uses mass but the new formula does not, it uses Volumes. The mass of matter is proportional to the Volume of matter, so some people mistake mass for a source of gravity.

Rev. 2016.1.8

####
**
**

The Law of Gravity
The volume of baryons in a planet equals the volume of a fallen shell in 5 nanoseconds.

NV/tau = zA/t

N = number of baryons in planet

V = proton volume = 3.591364 * 10^{-45} cubic meters

tau = 5.131534 ns

z = height fallen = 1/2 a t^{2}

A = planet area = 4 π R^{2}

R = planet radius or any larger radius of a sphere centered on a planet

t = time for object falling

Experiments show that dropping an object at a radius R from a planet's center will cause it to fall z meters in t seconds. The average acceleration in that experiment is equal to the average velocity (z/t) in the test for the shell falling into the planet divided by the time growing out of the planet. That is gravity: a volume falling inwards divided by a time passing outwards.

NV/tau = zA/t = the momentum of free-space conservation

**NV/tau = ((1/2) a t**^{2}) * (4 π R^{2}) / t

End of Law, Revised January 8, 2016, Alan Folmsbee, Wailuku
The Law of Gravity The volume of baryons in a planet equals the volume of a fallen shell in 5 nanoseconds.

NV/tau = zA/t

N = number of baryons in planet

V = proton volume = 3.591364 * 10

^{-45}cubic meters

tau = 5.131534 ns

z = height fallen = 1/2 a t

^{2}

A = planet area = 4 π R

^{2}

R = planet radius or any larger radius of a sphere centered on a planet

t = time for object falling

Experiments show that dropping an object at a radius R from a planet's center will cause it to fall z meters in t seconds. The average acceleration in that experiment is equal to the average velocity (z/t) in the test for the shell falling into the planet divided by the time growing out of the planet. That is gravity: a volume falling inwards divided by a time passing outwards.

NV/tau = zA/t = the momentum of free-space conservation

^{2}) * (4 π R

^{2}) / t

Matter causes gravity. Protons and neutrons are matter with volume. Mass does not cause gravity; it is an area. The Law of Gravity is defined without mass. The acceleration of gravity (a) near a planet, depends on volumes of free space draining into baryons and time growing out of baryons.

The momentum conservation revealed on the page for "Newton's G Derived" is used to write the law of gravity.

V

_{1}/(1 second) = V_{2}/taup

_{1}= p_{2}= momentum conservation = volume per secondV

_{2}is volume of baryons in planetV

_{1}is a volume calculated after a 1 second experiment dropping an appleV

_{1}= zAz = height fallen in 1 second = (1/2 a t

^{2})z/(1 second) = average velocity in the experiment dropping an apple for 1 second

The derivative of z/(1 sec) is acceleration a

A is area of a sphere centered on the planet's center, with a radius R from the center of the planet (4 pi R

^{2})tau = 5.131534 nanoseconds = τ

###### tau = The Universal Constant for the Conservation of Graviticspansive Continuum Graviticspansive Continuum is conserved as the momentum of the vacuum

The momentum in a planet's baryons' volume equals the momentum of any shell around a planet, where a shell is a volume defined as the height fallen times the area of a spheroid centered on the planet's center. This momentum is not mass times velocity. Momentum is also volume divided by time. It's The Law of Gravity. Many distant planets and stars add their volume changes to the planet's local account of continuum fluid._{1}/dt = dp

_{2}/dt = acceleration factors

_{1}/dt = 2a pi R

^{2}

_{2}/dt = MV / mC

_{0}

C

_{0}= 5.131534 * 10^{-9}second^{2}C

_{0}= capensity of free space = tau * seconds2a π R

^{2}= MV / mC_{0}Solve for a = g = gravitational acceleration

g = MV / (2mC

_{0}π R^{2})## The Acceleration of Gravity from the Law

#
g = MV / (2 π m C_{0} R^{2})

For example, on Mars:
M = 0.641740*10

^{24}kilogram = mass of planetV = 3.591364*10

^{-45}meter^{3}= proton volumem = 1.673800*10

^{-27}kilogram = proton massC

_{0}= 5.131534*10^{-9}second^{2}C

_{0}= capensity of free space = τ*secondR = 3.396200*10

^{6}meterR = length from the planet center to the apple drop point

**g = 3.710000**meters per square second, from NASA experiments and calculationsUse the Law of Gravity to calculate g and compare it with NASA's g.

Multiply mantissa'a alone, then add exponents

g = 0.64174*3.591364/(2*3.141592654*1.673800*5.131534*1.153417)

g = 0.03702555 mantissa

add exponents

x = 24-45+27+9-13 = 2

so

**g = 3.702555**meter per second squared for MarsThat confirms The Law of Gravity.

g = (M/R

^{2})* (V/(2πC_{0}m)) = (MG/R^{2})The momentum in baryons equals the momentum of any shell around a planet, where a shell is a height fallen times the area of a spheroid centered on the planet's center.

The linear momentum in a proton equals the momentum of a shell that surrounds the proton. That is the law of gravity.

December 23, 2015, Alan Folmsbee, Wailuku

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